The thermal conductivity of plastics is about 1000 times
lower than that for the aluminum. If the fin efficiency is 95% for an aluminum
fin of 6 mm height, the height required for a similar (same thickness and cross
section) plastic fin for 95% fin efficiency would be:
(a) 6 mm (b) 0.006 mm (c) 0.2 mm (d) 0.5 mm (e) cant tell
Hint: Do not calculate the fin efficiency. Assume the heat
transfer coefficient as constant and same.
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