Python 3: Write a function one Sum which takes one input, n , and finds the sum: 1 + 11 + 111 + 1111 + … up to n digits of 1. For example: print ( one Sum (1)) 1 Which is 1 = 1. print ( one Sum (2)) 12 which is 1 + 11 = 12. print ( one Sum (3)) 123 which is 1 + 11 + 111 = 123. Hint: think about each element of the sum (1, 11, 111, for example) represented as a sum of powers of 10: 111 = 10^0 + 10^1 + 10^2 = 1 + 10 + 100
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